Linear Regression
What is linear regression
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If you’re interested read on, if you’re not, see yourself out. πͺ
This article is the first of a series covering fundamental machine learning algorithms. Each post will be split into two parts
 The idea and key concepts  Most people should be able to follow this section and learn how the algorithm works
 The maths  This is for the interested reader and will include detailed mathematical derivations followed by an implementation in Python
The idea and key concepts
Regression
is any algorithm that takes a collection of inputs and predicts an output.
Let’s say we are trying to predict how much a house π‘ will sell for in a desirable area of North London. We may know a few facts about the house e.g. the square footage of the house π , the square footage of the garden π³ and whether there is a garage π.
In machine learning we call these facts variables
or features
. Intuitively we may value the house using a combination of these features.
Linear regression uses a linear combination
of the features to predict the output. This just means summing up each feature value multiplied by a number (a coefficient
) to represent how important that feature is e.g
$$ \begin{aligned} \text{House Price} &= (Β£1000 * \text{π }) \\ & + (Β£50 * \text{π³}) \\ & + (Β£1000 * \text{π?}) \end{aligned} $$
In this example the house price is calculated as $Β£1000$ for each square foot of the house plus $Β£50$ for each foot in the garden plus $Β£1000$ if there is a garage. If we took a nice $600$ square foot property with a small $500$ square foot garden and no garage our linear regression model would predict the house is worth $Β£625,000$.
$$ \begin{aligned} \text{House Price} &= (Β£1000 * \text{π }) + (Β£50 * \text{π³}) + (Β£1000 * \text{π ?}) \\ &= (Β£1000 * 600) + (Β£50 * 500) + (Β£1000 * 0)\\ &= Β£625,000 \end{aligned} $$
Now that’s how the linear regression model works! The question now is how do you choose the coefficients for the features, in our example the $1000$ the $50$ and the $1000$? π€·ββοΈ
A common type of machine learning algorithm called supervised learning algorithms
find these parameters using training data
. Training data is just examples where you already know the answer. In our case it is a list of houses where we know both the house features and the house prices in advance. Here is an example of three training examples with the model predictions:
House size π  Garden size π³  Garage? π  True House Price π°  Predicted house price π° 

1000  700  Garage  Β£1m  Β£ 1.036m 
770  580  No Garage  Β£0.75m  Β£0.799m 
660  200  Garage  Β£0.72m  Β£0.671m 
We want to chooses the coefficients to minimise the average error
when predicting the house price for all the training examples. This average error
is also known as the cost
and can be defined in different ways.
To better visualise the error associated with a prediction it is easier to see in a graph. To make the visualisation easier let’s assume that we only know one feature  the house size  for each training example.
The linear regression model in this case can be written as:
$$ \text{House Price} = \text{Price per Sq. ft.} * \text{Size} $$
Below I have plotted 20 example houses in green showing the price on the yaxis and the house size (in square feet) on the xaxis. I have also plotted the line of best fit (the linear regression model) with the predictions marked as black circles. The red lines shows the absolute error between the predictions and the true house price.
You can vary the price per square foot (the coefficient in the model) to see how this impacts the average error.
Average error
The best coefficients  that minimise the error  can be found by solving an equation called the normal equation
or by gradient descent
.
Gradient descent works by iteratively changing the coefficients to reduce the error between the predictions and the true house prices. The specifics of this process requires more maths and is detailed in the next section. I haven’t gone into the normal equations in this post.
In short the linear regression algorithm chooses the coefficients to minimise the average error
when predicting the house prices for all the training examples.
And that’s linear regression!
The maths
In order to keep this as accessible as possible to people less familiar with mathematical concepts and notation I will include footnotes to explain where I think it may help.
The model
If we let $y$ represent a single continuous target variable and $x_1,\dots,x_n$ (where $n \in \mathbb{N}$^{1} and $x_0 = 1$) represent the feature values. Then the linear model can be written as
$$ \begin{align} \hat{y}&=\beta_0x_0+\cdots+\beta_nx_n \\ \hat{y}&=\sum^{n}_{i=0}\beta_ix_i \end{align} $$
A hat above a variable is often used to represent a prediction of the true value. Here the y hat represents the linear model prediction.
The cost function
We define below the cost
(a.k.a. error
or loss
) function $J$ as half of the mean square error
for the $m$ training samples where $m \in \mathbb{N}$. We use a superscript to represent each training example so $y^j$ is the $j$th training data target value and $x_i^j$ is the $i$th feature value of the $j$th training example.
$$ \begin{align} J(\boldsymbol{\beta}) &= \frac{1}{2m}\sum^{m}_{j=1}\left( y^j\hat{y}^j \right)^2\\ &= \frac{1}{2m}\sum^{m}_{j=1}\left( y^j\sum^{n}_{i=0}\beta_ix_i^j \right)^2 \end{align} $$
Gradient descent
In order to find the coefficients that lead to the minimal cost we use gradient descent
. The gradient
of the cost function tells you in which direction to change your coefficients in order to reduce the value of the cost function the most. The gradient is defined as the vector of partial derivatives
with respect to each coefficient so let’s first calculate these:
$$ \begin{align} \frac{\partial J}{\partial\beta_k}\left(\boldsymbol{\beta}\right) &= \frac{\partial}{\partial\beta_k}\left( \frac{1}{2m}\sum^{m}_{j=1} \left( y^j\sum^{n}_{i=0}\beta_ix_i^j \right)^2 \right)\\ &= \frac{1}{m}\sum^{m}_{j=1} \left( y^j\sum^{n}_{i=0}\beta_ix_i^j \right)(x^j_k)\\ \end{align} $$
Now we can write the gradient as:
$$ \begin{aligned} \nabla_{\boldsymbol{\beta}} J &= \begin{bmatrix} \frac{\partial J}{\partial\beta_0} \\ \vdots \\ \frac{\partial J}{\partial\beta_n} \end{bmatrix} \\ &= \begin{bmatrix} \frac{1}{m}\sum^{m}_{j=1} \left(y^j\sum^{n}_{i=0}\beta_ix_i^j\right)x^j_0\\ \vdots \\ \frac{1}{m}\sum^{m}_{j=1} \left(y^j\sum^{n}_{i=0}\beta_ix_i^j\right)x^j_n\\ \end{bmatrix} \end{aligned} $$
We could calculate the above gradient using the sums defined but it is more efficient for implementing if we vectorise
the calculation.
Vectorise
For this we define the design matrix
$\mathbf{X}$ by stacking the $m$ training examples on top of each other, so each row of $\mathbf{X}$ represents one training example and the columns represent the different features. We also define $\mathbf{y}$ the vector of target values by stacking the $m$ target variables on top of each other. Finally we also define the vector of $n+1$ coefficients $\boldsymbol{\beta}$. Where:^{2}
$$ \mathbf{X}\in\mathbb{R}^{m\times (n+1)}, \quad \mathbf{y}\in\mathbb{R}^{m\times 1}, \quad \boldsymbol{\beta}\in\mathbb{R}^{(n+1)\times1} $$
Or more visually
$$ \mathbf{X}=\begin{bmatrix} 1 & x_1^1 & x_2^1 & \dots & x_n^1 \\ 1 & x_1^2 & x_2^2 & \dots & x_n^2 \\ \vdots & \vdots & \vdots & \ddots & \vdots \\ 1 & x_1^m & x_2^m & \dots & x_n^m \\ \end{bmatrix} $$
and
$$ \mathbf{y}=\begin{bmatrix} y_1\\y_2\\\vdots\\y_m \end{bmatrix} \quad \boldsymbol{\beta} = \begin{bmatrix} \beta_0\\\beta_1\\\vdots\\\beta_n \end{bmatrix} $$
Now if we take the above gradient we derived above and rewrite it splitting the terms we see
$$ \nabla_{\boldsymbol{\beta}} J =\frac{1}{m} \begin{bmatrix} \sum^{m}_{j=1}y^jx^j_0\\ \vdots \\ \sum^{m}_{j=1}y^jx^j_n\\ \end{bmatrix}+ \frac{1}{m} \begin{bmatrix} \sum^{m}_{j=1}\sum^{n}_{i=0}\beta_ix_i^jx^j_0\\ \vdots \\ \sum^{m}_{j=1}\sum^{n}_{i=0}\beta_ix_i^jx^j_n \end{bmatrix}\\ $$
From this (I hope you can convince yourself, assuming you know matrix multiplication) we can write
$$ \begin{align} \nabla_{\boldsymbol{\beta}} J &=\frac{1}{m}\left( \mathbf{X}^T\mathbf{X}\mathbf{\boldsymbol{\beta}}\mathbf{X}^T\mathbf{y} \right)\\ &=\frac{1}{m}\mathbf{X}^T\left( \mathbf{X}\mathbf{\boldsymbol{\beta}}\mathbf{y} \right)\\ &=\frac{1}{m}\mathbf{X}^T\left( \mathbf{\hat{y}}\mathbf{y} \right) \end{align} $$
Where $\mathbf{\hat{y}} = \mathbf{X}\mathbf{\boldsymbol{\beta}}$ are the predictions of the linear model.
Now that we have derived the gradient formula π let’s implement gradient descent in python π to iteratively step towards the optimal coefficients.
Python implementation
We will build the implementation in an object oriented fashion defining a class for Linear regression. For the full code (with doc strings) it’s on github here.
class LinearRegression():
Next we define the __init__ method on the class setting the learning rate
. Remember the gradient tells you in which direction to change the coefficients. The gradient descent algorithm repeatedly updates the coefficients by stepping in the direction of negative gradient
. The size of the step is governed by the learning rate.
def __init__(self, learning_rate=0.05):
self.learning_rate = learning_rate
print('Creating linear model instance')
Next let’s define a method for the cost function
as defined above
def cost(self, y, y_pred):
m = y.shape[0]
cost = (1 / (2 * m)) * \
(y  y_pred).T @ (y  y_pred)
return cost
Next let’s define a method to calculate the gradient
of the cost function
def gradient(self, y, y_pred, X):
m = X.shape[0]
gradient = (1 / m) * \
X.T @ (y_pred  y)
return gradient
Before we define the fit
method to implement gradient descent
let’s define one last method which predicts the target variable $y$ given the current coefficients and features $X$
def predict(self, X):
y_pred = X @ self.beta
return y_pred
And finally here is the fit
method implementing n_iter
iterations of gradient descent.
def fit(self, X, y, n_iter=1000):
m, n = X.shape
print(f'fitting with m={m} samples with n={n1} features\n')
self.beta = np.zeros(shape=(n, 1))
self.costs = []
self.betas = [self.beta]
for iteration in range(n_iter):
y_pred = self.predict(X)
cost = self.cost(y, y_pred)
self.costs.append(cost[0][0])
gradient = self.gradient(y, y_pred, X)
self.beta = self.beta  (
self.learning_rate * gradient)
self.betas.append(self.beta)
And that’s it. Hereβs an example use of the class:
linear_regression = LinearRegression()
linear_regression.fit(X, y)
linear_regression.predict(X_new)
Thanks for reading! π Please get in touch with any questions, mistakes or improvements.

$\mathbb{N}$ means the natural numbers i.e. $0,1,2,3,\dots$ and $\in$ means “in”, so $n\in\mathbb{N}$ is notation for $n$ is in $0,1,2,3,\dots$. ↩︎

$\mathbb{R}$ represents any real value e.g. 2.5, 1367.324, $\pi$, … there are a lot! $\mathbb{R}^{n\times m}$ is a matrix with $n$ rows and $m$ columns. So $\boldsymbol{\beta}\in\mathbb{R}^{(n+1)\times1}$ means $\boldsymbol{\beta}$ is a vector of length $n+1$. $\mathbf{y}\in\mathbb{R}^{m\times 1}$ means y is a vector of length $m$. $\mathbf{X}\in\mathbb{R}^{m\times (n+1)}$ means $\mathbf{X}$ is a matrix with $m$ rows and $(n+1)$ columns. ↩︎